Dynamic Memory Allocation (Addressing)

Generally what we think is that when memory is dynamically allocated block of memory is reserved from base address to memory  size , which is dynamically allocated.
But it's wrong. When memory is dynamically allocated using malloc or new , memory is allocated into HEAP so base address is getting changed.And so sometime it will result in Error , Given code is best example to understand it

Coding :-

#include<string.h>

#include<stdio.h>

#include<conio.h>

struct Student

{

    char Studname[40];

    float Studmark[10];

};

void setValues(struct Student* s, const char * name, float marks[], int nSubjects)

{

    int i=0;

    printf("Before Dynamic allocation - Address %u",s);

    s = (struct Student*)malloc(sizeof(struct Student));

    strcpy(s->Studname,name);

   // printf("\n%s %s",name,s->Studname);

    for(i=0;i<nSubjects;i++)

    {

        s->Studmark[i] = marks[i];

        printf("%f ",s->Studmark[i]);

    }

    //printf("\nAfter Address %u",s);

}

int main()

{

    struct Student ss[50];

    char str[100];

    int stud_No,sub_No,j,mark[10],i;

printf("\nEnter no of structure of student: ");

    scanf("%d",&stud_No);

printf("\nEnter no. of subjects in Structure: ");

    scanf("%d",&sub_No);

    for(i=0;i<stud_No;i++)

    {

        scanf("%s",str);

        for(j=0;j<sub_No;j++)

        {

            scanf("%f",&mark[j]);

        }

        setValues(&ss[i],str,mark,sub_No);

    }

    //printf("\nMain Address %u",&ss[0]);

    ss[0];

    printf("as %s",ss[0].Studname);

}